python - code for counting number of sentences, words and characters in an input file -

i have written following code count number of sentences, words , characters in input file sample.txt, contains paragraph of text. works fine in giving number of sentences , words, not give precise , correct number of characters ( without whitespaces , punctuation marks)

lines,blanklines,sentences,words=0,0,0,0 num_chars=0
  
print '-'*50
  
try:     filename = 'sample.txt'     textf = open(filename,'r')c except ioerror:     print 'cannot open file %s reading' % filename     import sys     sys.exit(0)
  
for line in textf:     print line     lines += 1     if line.startswith('\n'):         blanklines += 1     else:
  
    sentences += line.count('.')+ line.count ('!')+ line.count('?')      tempwords = line.split(none)     print tempwords      words += len(tempwords) 
  
textf.close()
  
print '-'*50 print "lines:", lines print "blank lines:",blanklines print "sentences:",sentences print "words:",words
  
import nltk import nltk.data import nltk.tokenize
  
with open('sample.txt' , 'r') f:     line in f:         num_chars += len(line)
  
num_chars = num_chars - (words +1 )
  
pcount = 0 nltk.tokenize import treebankwordtokenizer open('sample.txt','r') f1:     line in f1:         #tokenised_words = nltk.tokenize.word_tokenize(line)         tokenizer = treebankwordtokenizer()         tokenised_words = tokenizer.tokenize(line)     w in tokenised_words:         if ((w=='.')|(w==';')|(w=='!')|(w=='?')):             pcount = pcount + 1 print "pcount:",pcount num_chars = num_chars - pcount print "chars:",num_chars

pcount number of punctuation marks. can suggest changes need make in order find out exact number of characters without spaces , punctuation marks?

you can use regex replace non-alphanumeric characters , count number of characters in each line.