c++ - how does overloading of const and non-const functions work? -

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the stl full of definitions this:

iterator begin (); const_iterator begin () const;

as return value not participate in overloading resolution, difference here function being const. part of overloading mechanism? compiler's algorithm resolving line like:

vector<int>::const_iterator = myvector.begin();

in example gave: 

vector<int>::const_iterator = myvector.begin();

if myvector isn't const non-const version of begin() called , relying on implicit conversion iterator const_iterator.


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