scripting - How would i parse a multiline stdout string with a variable in bash script, i am getting error "unary operator expected" -

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i have bash script:

  #!/bin/bash java_version="1.6.0_17" _stdout=`java -version`  if [ $java_version = $_stdout ];         echo "matched" else         echo "not matched" fi

i result:

 java version "1.6.0_17" openjdk runtime environment (icedtea6 1.7.5) (rhel-1.16.b17.el5-x86_64) openjdk 64-bit server vm (build 14.0-b16, mixed mode) t4.sh: line 8: [: 1.6.0_17: unary operator expected not matched

how match $java_version $_stdout when $_stdout has multiple lines

use quotes.

#!/bin/bash java_version="1.6.0_17" _stdout=`java -version`  if [ "$java_version" = "$_stdout" ];         echo "matched" else         echo "not matched" fi

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