mysql - Selecting last version of entry in different language from sql database -

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is there way in 1 sql query? newest (version) of same entry in every language available.

my table , example data is: 

id  |  index  |  version  |  language  | ... ------------------------------------------------ 1        1          1            1         test1 2        1          2            1         test2 3        2          1            1         test3 4        2          1            2         test4 5        2          1            3         test5 6        2          2            3         test6 7        3          1            1         test7 8        3          1            2         test8
  • id unique identifer
  • index unique entry in database means time versions , language version of same article/entry share same index.
  • version version number. 1 first version , greater number newer.
  • language number of language version of entry/article.

i can't think of way in 1 query. maybe it's feasible?

i this:

id  |  index  |  version  |  language  | ... ------------------------------------------------ 2        1          2            1         test2 3        2          1            1         test3 4        2          1            2         test4 6        2          2            3         test6 7        3          1            1         test7 8        3          1            2         test8

test1 out because test2 in same language , it's newer
test5 out because test6 newer in same language

resolved

select t1.* entry_view t1  left join entry_view t2 on (t1.version < t2.version , t1.id_language = t2.id_language , t1.`index` = t2.`index`) t2.id null 

    select t1.id, t1.index, t1.version, t1.language table t1  left join table t2 on (t1.id < t2.id , t1.language = t2.language)  t2.id null

edit: assumed ids increasing , newest 1 last.

maybe try this:

select t1.id, t1.index, t1.version, t1.language table t1  left join table t2 on (t1.version < t2.version , t1.language = t2.language)  t2.id null

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